Water is compressible; it has a bulk modulus of about 2.2 GPa. So at the 1086 bar at the bottom of the Mariana trench (~109 MPa), it'll have compressed about (109 / 2200) ~= 5%. Materials with a different bulk modulus to water may start to float at sufficiently high depths.
Water does change density with temperature, so it is denser the deeper you go. I doubt there's a normal bowling ball weight that would have the right density for it to float at some random depth though.
It sank to the bottom
There was no depth where it floated? Interesting.
Water's not compressible, so the density doesn't change with depth. Either the bowling ball is denser than water or less dense than water.
Water is compressible; it has a bulk modulus of about 2.2 GPa. So at the 1086 bar at the bottom of the Mariana trench (~109 MPa), it'll have compressed about (109 / 2200) ~= 5%. Materials with a different bulk modulus to water may start to float at sufficiently high depths.
https://en.wikipedia.org/wiki/Bulk_modulus#Selected_values
Water does change density with temperature, so it is denser the deeper you go. I doubt there's a normal bowling ball weight that would have the right density for it to float at some random depth though.
Therefore no there isn't a depth where the weight of the seawater above compresses the water to a density equal to that of the bowling ball
It would probably end up right next to the tape measure I've been looking for since Sunday.
Trying to measure how deep the trench is?
Were you on a boat over the Mariana Trench on Sunday?
A diversion to average bowling ball but no tungsten bowling ball? Outrageous.
Thanks. Now I know that bowling balls float.
I was more interested if it would compress than where they floated
I think these calculations could be wrong, considering that the ball would either absorb water and decrease in density or implode / break