Spyke
discuss.tchncs.de

Cool thought, and good job!

Of course, it's trivial to prove that 6x4 isn't possible, and naturally I instantly constructed in my head a rigorous proof of this obvious fact. But uhh, just for fun and maybe for the weaker mathematicians in the room (not me, certainly!), how would you go about proving that?

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I guess start with placing the minimum 3x5 required for 8 and 7 to work, whether with missing mine facing up or right? There is only a handful of options from there and it's trivial enough to go through them.

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The smallest possible rectangle board with all 8 numbers and a blank spot (custom-made) | Spyke