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how to get a specific item of a list
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that's got it! thanks muchly
Comment on
how to get a specific item of a list
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that's got it! thanks muchly
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consumable list only providing one item
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Yes. That works great! Thanks again!
Since I'm wanting to be able to use this multiple times, for various lists, I end up with:
AdjectiveNoun(Adj, Noun)=>
let combo=[];
for(const a of Adj.selectAll) {
for(const n of Noun.selectAll) {
combo.push([a,n].join(' '));
};
};
return [joinlists(combo).consumableList];
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consumable list only providing one item
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Thanks @Almaumbria.
Unfortunately, it's not quite what I wanted. I'm wanting the effect of a consumable list where the elements are all the combinations of Adjective+Noun. I think I'll have to figure out how to iterate through each of Adjective and Noun and construct a new list with all the combinations and stash that. I've not written an function like Thing() before, so I'll have to think about that.
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consumable list only providing one item
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That's looking very promising! I can't try it right now, but I think it'll do, once I parameterize the function to allow passing in the two lists to be combined.
Thanks muchly!
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[Suggestion(ish)] Start new generators private instead of public
People (myself included) are lazy and usually won't bother to make a change unless they have a specific reason. If the default were private then we wouldn't have the huge compendium of interesting pages to look through that we do.
Please keep the default public.