Energy in noise canceling headphones
For a long time, noise canceling headphones have intrigued me. I do understand the principle of calculating a sound wave to interfere destructively with the noise. It just feels astonishing to me that it can be done quickly enough in such a small space. A great feat of engineering!
Anyway, I just started to wonder about the energy. The original noise carries energy, and so does the canceling wave. Outside the target area they do whatever, but inside it the waves cancel each other (not perfectly, but still). What is left supposedly carries less energy. So where does the rest go?
My guess goes to the usual suspect: the energy is converted to a bit of heat and quickly dissipates to the surrounding air and flesh and plastic and whatever is there. Is this right? And as a funny additional question: how loud would the noise have to be for the headphone wearer to feel this heat?