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26 replies

kbin.social

And we're already posting screenshots of reddit posts that are screenshots of tiktoks. Awesome

21

Why go to all that trouble when you can just take a screenshot and repost it here? (Or throw it onto discord, either/or)

3
kbin.social

For x in range(∞):
If x % 2 == 0:
Print('Even')
Else:
Print('Opposite of even')

7
lemmy.world

I feel like I accidentally do something similar everytime I program anything. I am just bad at it, I don't know the short cuts or all the commands, but by God, it will work when I am done with it... maybe.

I don't know the right wat to do this, but I think there would be something like:

x = Number

If (x//2)is.integer() == "true":

Print("Even")

Else:

Print("odd")

Maybe? Idk. Probably a bunch of syntax issues and I haven't written anything in like a year.

5
neroreply
lemmy.world

You basically got it yeah. You can do x % 2 and check if that is 0, as % calculates the remainder (in python at least)

4
lemmy.world

y = 1

while y ==1:

x = input("Enter Number")

if int(x) % 2 == 0:
   

print("EVEN")

else:
    

print("ODD")

I don't know why, but I opened up my IDLE for the first time in a year and did it.

2
int val = 3;
bool is_odd = val & (decltype(val))0x01 == (decltype (val))1;
1
neroreply
lemmy.world

Know you probably don’t care, but you can do a while loop using while True:

Which is the same as you using a statement which equals to true.

Thought i don’t think you need it for what you’re doing currently.

1

Unless you want it to keep asking the question of course**

1

A place shall not be called "programmer humor" without an odd-even joke

3

This is literally how I code stuff when I'm sleepy, then I come back a month later and realize how horrible the code was. Pretty sure I can still find stuff like this in my old discontinued projects that I haven't cleaned up

1

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