Spyke

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17 replies

lemm.ee

That is why I use just int main(){...} without arguments instead.

39

void main(){...} is not in the standard, but works on both MSVC and GCC (with warnings). I think it works on both C/C++, but you really shouldn’t use it in production. Just use int main(void){...} , without any return value, which is permitted in the standard, and will return success iirc.

4
lemmy.world

i will never forgive C for making the type syntax be

char* args[]

instead of the much more reasonable

&[char] args 

it also bothers me that char* args[] and char c are “the same type” in the sense that the compiler lets you write

char c, *args[5];

with no problems. i think the C languages would be way easier to learn if they had better type syntax. don’t even get me started on C++ adding support for

auto fn_name() -> ReturnType { … }
6
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lemmy.world

god, what a beautiful language. it brings a tear to my eye

5

I personally think that C++ can be beautiful. For example: std::filesystem::path overrides the / operator, for specifying parent paths. It’s the same as Kotlin’s OKIO and Pythons standard pathlib.

3
lemmy.ml

It could, but not necessarily.

char **args can just mean you have a pointer which points to an address, and at that address, you can get a second address. Follow the second address, there is a char saved there.

On the other hand, char *args[] means " follow this address to find a list of characters".

2

@racketlauncher831 As far as the C compiler is concerned, there is literally no difference between those two notations. If you declare a function parameter as an array (of T), the C compiler automatically strips the size information (if any) and changes the type to pointer (to T).

(And if we're talking humans, then char *args[] does not mean "follow this address to find a list of characters" because that's the syntax for "array of pointers", not "pointer to array".)

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